Question

Solve 8 sinx= square root 3 /cosx + 1/sinx​

Answer 1

Step-by-step explanation:

8 sin^2 x . cos x = √3 sin x + cos x

( 4 sin x) ( 2 sin x cos x) = √3 sin x + cos x

2 sin A . sin B = ( cos A - B) - ( cos A + B)

2 [ cos x - cos 3 x ] = √3 sin x + cos x

2cosx - 2cos 3x = √3 sin x + cos x

cos x - √3 sin x = 2 cos 3x

1/2 cos x - √3/2 sin x = cos 3x

(cos π/2 cos x - sin π/3 sin x) = cos 3x

cos ( x + π/3) = cos 3x

cos theta = cos alpha

theta = 2nπ ( + , - ) alpha

theta = x + π/3 = 2nπ +-3x

1. x + π/3 = 2nπ +3x

2x = -2nπ + π/3

x= -nπ + π/6

2. x + π/3 = 2nπ -3x

4x = 2nπ -π/3

x=nπ/2 -π/12