Question

Solve : 8^x-1=2^x+3​

Answer 1

${8}^{x} - 1 = {2}^{x} + 3$

$= > { ({2}^{3} )}^{x} = {2}^{x} + 3 + 1$

$= > {2}^{3x} = {2}^{x} + 4$

$= > {2}^{3x} = {2}^{x} + {2}^{2}$

Now, when bases are same powers are added.

$= > 3x = x + 2$

$= > 3x - x = 2$

$= > 2x = 2$

$= > x = \frac{2}{2}$

$= > x = 1$

Hence, this is the required answer

Answer 2

Answer:

x = 3

Step-by-step explanation:

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