Question

solve 8 (x^2+1\x^2)-42(x-1/x)+29=0​

Answer 1

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

(8x^2+8/x^2)-(42x-42/42x)+29=0

8x^2+8/x^2-42x+42/42x+29=0

Answer 2

Answer:

[tex] {8x }^{2} + \frac{8} {x}^{2} 42x - 42 \frac{42}{42x} + 29 = 0 \\

\\ = 8x + \frac{8}{ {x}^{2} - 42x \frac{42}{42x} + 29 = 0[/tex

please mark my answer as a brain list