Question

solve 8b-3÷2b+5=-19​

Answer 1

Answer:

8b-3/2b+5=-19

We move all terms to the left:

8b-3/2b+5-(-19)=0

Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R

We add all the numbers together, and all the variables

8b-3/2b+24=0

We multiply all the terms by the denominator

8b*2b+24*2b-3=0

Wy multiply elements

16b^2+48b-3=0

a = 16; b = 48; c = -3;

Δ = b2-4ac

Δ = 482-4·16·(-3)

Δ = 2496

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

b1=−b−Δ√2ab2=−b+Δ√2a

The end solution:

Δ−−√=2496−−−−√=64∗39−−−−−−√=64−−√∗39−−√=839−−√

b1=−b−Δ√2a=−(48)−839√2∗16=−48−839√32

b2=−b+Δ√2a=−(48)+839√2∗16=−48+839√32