Math, asked by sadiajamil2004, 4 months ago

solve 8x^2-2x^2-5x-1=0​

Answers

Answered by surajpjadhav800
0

Answer:

Factoring 8x2-5x-1

The first term is, 8x2 its coefficient is 8 .

The middle term is, -5x its coefficient is -5 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 8 • -1 = -8

Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is -5 .

-8 + 1 = -7

-4 + 2 = -2

-2 + 4 = 2

-1 + 8 = 7

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

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