solve 8x^2-2x^2-5x-1=0
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Factoring 8x2-5x-1
The first term is, 8x2 its coefficient is 8 .
The middle term is, -5x its coefficient is -5 .
The last term, "the constant", is -1
Step-1 : Multiply the coefficient of the first term by the constant 8 • -1 = -8
Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is -5 .
-8 + 1 = -7
-4 + 2 = -2
-2 + 4 = 2
-1 + 8 = 7
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
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