Solve 8x + 3y = 11 ; 3x – y = 2
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8x+3y=11---1
3x-y=2----2
by elimination method
x=1
and sub in 1
8x+3y=11
8 (1)+3y=11
8+3y=11
3y=11-8
3y=3
y=1
3x-y=2----2
by elimination method
x=1
and sub in 1
8x+3y=11
8 (1)+3y=11
8+3y=11
3y=11-8
3y=3
y=1
Answered by
1
Answer:
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Step-by-step explanation:
Hello friends..
____________________________
==> 8x + 3y = 11 ....................(I)
==> 3x - y = 2 ...................(II)
In equation (II) it is easy to express y in terms of x.
3x - y = 2
3x -2 = y
Substituting y = 3x - 2 in equation (I)
8x + 3y = 11
8x + 3(3x - 2) = 11
8x + 9x - 6 = 11
17x - 6 = 11
17x = 11+6
17x = 17
x = 17/17
x = 1
Now,substituting the value of x in the equation y = 3x - 2
y = 3x - 2
y = 3 x 1 - 2
y = 3 - 2
y = 1
So,x = 1 and y = 1 are the solution of the given equation..
Thanks..
:)
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