Math, asked by csvc10a26amrut, 7 months ago

solve:8x+3y=33; 7x+2y=27​

Answers

Answered by sunnyk88774
4

Answer:

x=3andy=3

Step-by-step explanation:

8x+3y=33 and 7x+2y=27

8x+3y=33×2

7x+2y=27×3

=5x=15

x=3 similarly y=3

Answered by venkateshwarlu201
2

Step-by-step explanation:

8x+3y =33.........(1) , 7x+2y = 27.....(2)

from eq.(1)

8x = 33-3y

x =(33-3y)/8........(3)

substituting eq.(3) in (2)

7[(33-3y)/8]+2y=27

(231-21y)/8+2y=27

[231-21y+16y]/8=27

231-5y/8=27

231-5y=216

-5y = 216-231

-5y=-15

y=15/5

y=3

now substitute'y' value in eq.3

x = 33-3(3)/8

x= 33-9/8

= 24/8

= 3

Therefore x=3 and y=3

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