solve:8x+3y=33; 7x+2y=27
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Answered by
4
Answer:
x=3andy=3
Step-by-step explanation:
8x+3y=33 and 7x+2y=27
8x+3y=33×2
7x+2y=27×3
=5x=15
x=3 similarly y=3
Answered by
2
Step-by-step explanation:
8x+3y =33.........(1) , 7x+2y = 27.....(2)
from eq.(1)
8x = 33-3y
x =(33-3y)/8........(3)
substituting eq.(3) in (2)
7[(33-3y)/8]+2y=27
(231-21y)/8+2y=27
[231-21y+16y]/8=27
231-5y/8=27
231-5y=216
-5y = 216-231
-5y=-15
y=15/5
y=3
now substitute'y' value in eq.3
x = 33-3(3)/8
x= 33-9/8
= 24/8
= 3
Therefore x=3 and y=3
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