Math, asked by panthhaveliwala13, 2 months ago

solve 8x+5y=9, Kx+10y=18​

Answers

Answered by bethaustin55
2

Answer:

8X+5Y=9

MULTIPLY BY 2 ON BOTH SIDE

16X + 10Y = 18

USING ELIMINATION METHOD

16X-KX +10Y-10Y =18-18

(16-K)X = 0

X=0

Step-by-step explanation:

Answered by aimanbutt
0

The given system of equations is:

8x + 5y – 9 = 0

kx + 10y – 18 = 0

The above equations are of the form

a1 x + b1 y − c1 = 0

a2 x + b2 y − c2 = 0

Here, a1 = 8, b1 = 5, c1 = -9

a2 = k, b2 = 10, c2 = -18

So according to the question,

So according to the question, For unique solution, the condition is

a1/a2 = b1/b2 = c1/c2

8/k = 5/10 = -9/-18 = 1/2

⇒ k = 16

Hence, the given system of equations will have infinitely many solutions, if k =16

HOPE IT HELPS .

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