solve 8x+5y=9, Kx+10y=18
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Answer:
8X+5Y=9
MULTIPLY BY 2 ON BOTH SIDE
16X + 10Y = 18
USING ELIMINATION METHOD
16X-KX +10Y-10Y =18-18
(16-K)X = 0
X=0
Step-by-step explanation:
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The given system of equations is:
8x + 5y – 9 = 0
kx + 10y – 18 = 0
The above equations are of the form
a1 x + b1 y − c1 = 0
a2 x + b2 y − c2 = 0
Here, a1 = 8, b1 = 5, c1 = -9
a2 = k, b2 = 10, c2 = -18
So according to the question,
So according to the question, For unique solution, the condition is
a1/a2 = b1/b2 = c1/c2
8/k = 5/10 = -9/-18 = 1/2
⇒ k = 16
Hence, the given system of equations will have infinitely many solutions, if k =16
HOPE IT HELPS .
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