Question

solve 8y+4=3(y-1)+7
pls ans the question its very very imp for me

Answer 1

Answer:

Step-by-step explanation:

8y+4=3(y-1)+7

8y+4=(3y-3)+7

8y+4=3y-3+7

8y+4=3y+4

8y-3y=4-4

5y=0

y=0/5

y=0

Answer 2

Answer:

The correct answer will be y =0.

Step-by-step explanation:

Given the question is -

To solve a linear equation in one variable which is y.

The given linear equation is -

$8y +4=3(y-1)+7$

Solving the bracket -

$8y+4= 3y-3+7$

Now moving the terms with y on LHS (Left Hand Side) and remaining on RHS (Right Hand Side) -

$8y-3y = -3+7-4$

Now doing addition and subtraction we will get -

$5y = 0\\\\y = 0$

So the solution of the equation is y = 0.

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