Question

solve (9^0-7^0)×9+7 laws ​

Answer 1

Answer:

(ii) (1/3)-4

(iii) (5/2)-3

(iv) (-2)-5

(v) (-3/4)-4

We have:

(i) 5-3 = 1/53 = 1/125

(ii) (1/3)-4 = (3/1)4 = 34 = 81

(iii) (5/2)-3 = (2/5)3 = 23/53 = 8/125

(iv) (-2)-5 = 1/(-2)-5 = 1/-25 = 1/-32 = -1/32

(v) (-3/4)-4 = (4/-3)4 = (-4/3)4 = (-4)4/34 = 44/34 = 256/81

2. Evaluate: (-2/7)-4 × (-5/7)2

Solution:

(-2/7)-4 × (-5/7)2

= (7/-2)4 × (-5/7)2

= (-7/2)4 × (-5/7)2 [Since, (7/-2) = (-7/2)]

= (-7)4/24 × (-5)2/72

= {74 × (-5)2}/{24 × 72 } [Since, (-7)4 = 74]

= {72 × (-5)2 }/24

= [49 × (-5) × (-5)]/16

= 1225/16

Answer 2

Answer:

7

Step-by-step explanation:

9^0 = 1

7^0 = 1

so,

(9^0-7^0)

= (1-1) ×9+7

= 0×9 +7

= 7