Math, asked by anaghanayak05, 5 months ago

solve 9*3^x=(27) ^2 using exponents​

Answers

Answered by Jha28utkarsh
0

9 × 3^x = ( 27 ) ^ 2x -3

9 × 3^x = ( 3 ) ^3(2x-3)

3² × 3^x = ( 3 )^ 6x - 9

3^(2+x)= 3^(6x-9)

since a^m × a ^n = a^(m+n)

we know that,  

if a^m = a^n then m= n  

2+x = 6x-9  

x-6x = -9-2

-5x = -11

x = (-11)/(-5)

therefore,

x = 11/5

                                                                             

I hope this helps you.  

Answered by Anonymous
5

Answer:

9×3x= 27²

solɴ:-

──────

──────

=> 9×3x= 729

=> 3x = 729/9

=>3x = 81

=> x = 81/3

=>x = 27

∴x= 27

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