solve 9*3^x=(27) ^2 using exponents
Answers
Answered by
0
9 × 3^x = ( 27 ) ^ 2x -3
9 × 3^x = ( 3 ) ^3(2x-3)
3² × 3^x = ( 3 )^ 6x - 9
3^(2+x)= 3^(6x-9)
since a^m × a ^n = a^(m+n)
we know that,
if a^m = a^n then m= n
2+x = 6x-9
x-6x = -9-2
-5x = -11
x = (-11)/(-5)
therefore,
x = 11/5
I hope this helps you.
Answered by
5
Answer:
9×3x= 27²
solɴ:-
──────
──────
=> 9×3x= 729
=> 3x = 729/9
=>3x = 81
=> x = 81/3
=>x = 27
∴x= 27
Similar questions
Math,
2 months ago
Social Sciences,
2 months ago
Math,
2 months ago
Social Sciences,
5 months ago
Sociology,
5 months ago
Math,
11 months ago
English,
11 months ago