Math, asked by botwabagdogra, 9 months ago

solve : 9/4a^2 + 49/9p^2-7ap
please help with this question ​

Answers

Answered by KrishnaKumar01
0

Answer:

100

Step-by-step explanation:

hope it helps you friend

Answered by Anonymous
1

Step-by-step explanation:

its factorisatipn

its factorisatipn9/4a^2 = (3/2a)^2

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^2

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole square

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2a

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2aand b= 7/9p

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2aand b= 7/9pso the final factorisation is

its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2aand b= 7/9pso the final factorisation is (3/2a-7/3p)^2

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