solve : 9/4a^2 + 49/9p^2-7ap
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Answers
Answer:
100
Step-by-step explanation:
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Step-by-step explanation:
its factorisatipn
its factorisatipn9/4a^2 = (3/2a)^2
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^2
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole square
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2a
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2aand b= 7/9p
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2aand b= 7/9pso the final factorisation is
its factorisatipn9/4a^2 = (3/2a)^249/9p^2 =( 7/3p)^27ap = 2(3/2a)(7/3p)so (3/2a)^2 +(7/9p)^2 - 2(3/2a)(7/3p)its in the form of a-b whole squarewhere a = 3/2aand b= 7/9pso the final factorisation is (3/2a-7/3p)^2