Question

solve (9^5)^x =(9^4)^x/9^2

Answer 1

Answer:

HEY MATE!.......

\begin{lgathered}given \: .... \\ 11(x + 3) - 4(x - 9) + 5(x + 2) = 0 \\ 11x + 33 - 4x + 36 + 5x + 10 = 0 \\ 12x + 79 = 0 \\ 12x = - 79 \\ x = \frac{ - 79}{12} \: or \: - 6.58\end{lgathered}

given....

11(x+3)−4(x−9)+5(x+2)=0

11x+33−4x+36+5x+10=0

12x+79=0

12x=−79

x=

12

−79

or−6.58

hope it helps u dear.....

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Answer 2

$\huge\purple{\mathbb{AnsWer:}}$

$({ {9}^{5} })^{x} = \frac{ ({ {9}^{4} })^{x} }{ {9}^{2} } \\ ⟹ {9}^{5x} = {9}^{4x - 2} \\ ⟹ 5x = 4x -2 \\ ⟹5x - 4x = - 2 \\ ⟹x = - 2$

$\bold\pink{\boxed{Hence,\:the\:answer\:is\:x=-2}}$

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