Question

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Answer 1

Answer:

Answer in the attachment

Hope it helps you

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Answer 2

$\huge\mathfrak\red{YOUR ANSWER}$

the sum of first 15 multiples of 8 is...

8+16+24+32+.....

since the difference of all will be same we can use a formula....

$sn = \frac{n}{2} (2a + (n - 1)d)$

here n( total numbers) = 15 , a=8

and d(difference) =16-8=8

putting values....

$= \frac{15}{2} (2 \times 8 + (15 - 1) \times 8)$

$= \frac{15}{2} (16 + 14 \times 8)$

$= \frac{15}{2} (16 + 112)$

$\frac{15}{2} \times 128$

=960

soo, sum of first 15 multiples of 8 is 960...

Q.9....

sorry I am not able to do it but I'll try and answer you soon....

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