Question

solve 9x^2 -12x+4=0 by quadratic formula

Answer 1

On comparing 9x^2 - 12 x + 4 = 0 with ax^2 + bx + c = 0, we get :

a = 9   , b = - 12  , c = 4

Therefore, discriminant = b^2 - 4ac

                                         = ( - 12 )^2 - 4( 9 × 4 )  

                                         = 144 - 144

                                         = 0

Discriminant = 0

                            Applying quadratic formula,

x = $\dfrac{-b \pm \sqrt{discriminant}}{2a}$

 

x = $\dfrac{- ( - 12 ) \pm \sqrt{0}}{2( 9 ) }$

x = $\dfrac{ + 12 }{2( 9 )}$

x = $\dfrac{2}{3}$

As discriminant was 0, roots are real and equal. therefore roots are 2 / 3 and 2 / 3.

Answer 2

Answer:

here is your answer

Step-by-step explanation:

hope it will help you