Question

solve 9x2 +13x+4 by completing sqrs

Answer 1

$9 {x}^{2} + 13x + 4 \\ 9 {x}^{2} + 4x + 9x + 4 \\ x (9x + 4) + 1(9x + 4) \\ (9x + 4)(x + 1) \: \: \: \: \\ hope \: its \: help \\ plz \: mark \: me \: as \: brainliest \\ plz \: follow \: me \\ dfgh4$

Answer 2

✌️✌️ hey frnds.......

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$9x ^{2} + 13x + 4 = 0$

$\frac{ {9x}^{2} }{9} + \frac{13x}{9} + \frac{4}{9} = \frac{0}{9}$

${x}^{2} + \frac{13x}{9} + \frac{4}{9} = 0$

${x}^{2} + 2 \times x \times \frac{13}{18} + ({ \frac{13}{18} })^{2} - ( { \frac{13}{18} })^{2} + \frac{4}{9} = 0$

$( {x + \frac{13}{18} })^{2} = ( \frac{13}{18})^{2} - \frac{4}{9}$

$( {x + \frac{13}{18} })^{2} = ( \frac{169}{324}) - \frac{4}{9}$

$( {x + \frac{13}{18} })^{2} = \frac{169 - 144}{324}$

$( {x + \frac{13}{18} })^{2} = \frac{25}{324}$

$(x + \frac{13}{18} ) = + - \sqrt{ \frac{25}{324} }$

$x + \frac{13}{18} = + - \frac{5}{18}$

$x = + - \frac{5}{18} - \frac{13}{18}$

$by \: ( + ) \: sign \:$
$x = \frac{5}{18} - \frac{13}{18}$

$x = \frac{5 - 13}{18}$

$x = \frac{8}{18}$

$x = \frac{4}{9}$

$by \: ( - )sign$

$x = - \frac{ 5}{18} - \frac{13}{18}$

$x = \frac{ - 5 - 13}{18}$

$x = - \frac{18}{18}$

$x = - 1$

$hence \: the \: x \: is \: \frac{4}{9} \: and \: - 1.......$

I hope it's helpful ☺️☺️☺️✅