Math, asked by trivediheer781, 3 months ago

Solve 9x² +14x-8=0
by completing the square
method.​

Answers

Answered by tanishasankhe35
0

Answer:

(x) = 9x² + 14x - 8

By completing the square method:

\mathsf {x^2 + \frac{14}{9}x - \frac{8}{9} = 0 }x

2

+

9

14

x−

9

8

=0

\mathsf {(x + \frac{14}{18})^2 - (\frac{14}{18})^2 - \frac{8}{9} = 0}(x+

18

14

)

2

−(

18

14

)

2

9

8

=0

\mathsf {(x + \frac{14}{18})^2 - (\frac{14}{18})^2 - \frac{8}{9} = 0}(x+

18

14

)

2

−(

18

14

)

2

9

8

=0

\mathsf {(x + \frac{14}{18})^2 - \frac{196}{324} - \frac{8}{9} = 0}(x+

18

14

)

2

324

196

9

8

=0

\mathsf {(x + \frac{14}{18})^2 - (\frac{196 + 288}{324}) = 0}(x+

18

14

)

2

−(

324

196+288

)=0

\mathsf {(x + \frac{14}{18})^2 - \frac{484}{324} = 0}(x+

18

14

)

2

324

484

=0

\mathsf {(x + \frac{14}{18})^2 = \frac{484}{324}}(x+

18

14

)

2

=

324

484

\mathsf {x + \frac{14}{18} = ± \sqrt{\frac{484}{324}}}x+

18

14

324

484

\mathsf {x + \frac{14}{18} = ± \frac{22}{18}}x+

18

14

18

22

\mathsf {x = \frac{-14}{18} ± \frac{22}{18}}x=

18

−14

±

18

22

\mathsf {x = \frac{-14}{18} + \frac{22}{18} \:\:\:\:\:\:OR\:\:\:\:\frac{-14}{18} - \frac{22}{18}}x=

18

−14

+

18

22

OR

18

−14

18

22

\mathsf {x = \frac{8}{18} \:\:\:\:\:\:OR\:\:\:\:\: \frac{-36}{18}}x=

18

8

OR

18

−36

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