Solve : 9x²(5x+7)
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9x2(5x + 7)
Let p, q and r be three monomials.
Then, by distributive law of multiplication over addition, we have:
P × (q + r) = (p × q) + (p × r)
Now,
= (9x2 × 5x) + (9x2 × 7)
= (45x3 + 63x2) … [ ∵ am × an = am+n]
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