Solve : 9x² + 6x + 1 = 0.
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Answer:
x = -1/3 ; x = -1/3
Explanation:
9x² + 6x + 1 = 0
9x² + 3x + 3x + 1 = 0 (since, 3 * 3 = 9)
3x(3x + 1) +1(3x + 1) = 0
(3x + 1)(3x + 1) = 0
Therefore zeroes are =>
3x + 1 = 0 ; 3x + 1 = 0
3x = -1 ; 3x = -1
x = -1/3 ; x = -1/3
hope this helps !
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