Question

Solve 9x2-9(a+b)x+(2a2+5ab+2b2)=0 by factorisation

Answer 1

9 x² - 9 (a + b)  x + ( 2 a² + 5 a b + 2 b² ) =  0
9 x² - 9 (a + b)  x  + ( 2 a + b)  ( 2 b + a ) = 0

factors of  9 * (2a +b) ( 2 b + a ) are :  3 (2 a + b)  and 3 (2 b + a)
Their sum is  6a+3b + 6  b + 3 a = 9(a + b) = coefficient of x in the given equation.

Hence,  [x - 3(2a+b) ]  [ x - 3 (2b +a) ] = 0
  x =  3 (2a+b)  or  3 (2b+a)

Answer 2

Answer:

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