Question

Solve:

9y^2+6y-8=0

Please find the roots..​

Answer 1

Answer:

$9y \times 2 + 6y - 8 = 0 \\ \\ 18y + 6y - 8 = 0 \\ \\ 24y - 8 = 0 \\ \\ 24y = 8 \\ \\ y = \frac{8}{24} \\ \\ y = \frac{1}{3} . \: answer$

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Step-by-step explanation:

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Answer 2

Answer:

9y^2 + 6y -8 =0

9y^2 -6y+12y -8 =0

3y(3y -2 ) + 4(3y-2)

(3y-2 ) , (3y+4)

3y-2 =0 , 3y + 4=0

y = 2/3 , y = -4/3

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