Solve (a^2-b^2)^2 ( A ) (a^2+b^2)^2+2a^2b^2 ( B ) (a^2+b^2)^2+4a^2b^2 ( C ) (a^2+b^2)^2-4a^2b^2 ( D ) (a^2+b^2)^2-2a^2b^2
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Answer:
a²-b²=2a
I don't know answer
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Answer:
C) (a² + b²)² - 4a²b²
Step-by-step explanation:
(a² - b²)²
= (a²)² + (b²)² - 2a²b² (∵ (a-b)² = a² + b² -2ab)
= (a²)² + (b²)² - 2a²b² + 2a²b² - 2a²b² ( add and subtract 2a²b²)
= (a²)² + (b²)² + 2(a²)(b²) - 4a²b²
= (a² + b²)² - 4a²b²
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