Math, asked by Dhidhi5792, 10 months ago

Solve (a^2-b^2)^2 ( A ) (a^2+b^2)^2+2a^2b^2 ( B ) (a^2+b^2)^2+4a^2b^2 ( C ) (a^2+b^2)^2-4a^2b^2 ( D ) (a^2+b^2)^2-2a^2b^2

Answers

Answered by shivam88635
0

Answer:

a²-b²=2a

I don't know answer

Answered by spiderman2019
0

Answer:

C) (a² + b²)² -  4a²b²

Step-by-step explanation:

(a² - b²)²

= (a²)² + (b²)² - 2a²b²                              (∵ (a-b)² = a² + b² -2ab)

= (a²)² + (b²)² - 2a²b²  + 2a²b² - 2a²b² ( add and subtract 2a²b²)

= (a²)² + (b²)² + 2(a²)(b²)  - 4a²b²

= (a² + b²)² -  4a²b²

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