Math, asked by keshavkharbanda, 10 days ago

solve a^2b/x^2 + (1-b/x)a = 2b - a^2/x​

Answers

Answered by swapnamatoor
4

Step-by-step explanation:

(a+2b)x+(2a−b)y=2

⇒y=

2a−b

2−ax−2bx

(a−2b)x+(2a+b)y=3

⇒(a−2b)x+(2a+b)×

2a−b

2−ax−2bx

=3

2a−b

(ax−2bx)(2a−b)+(2a+b)(2−ax−2bx)

=3

⇒2a

2

x−4abx−abx+2b

2

x+4a+2b−2a

2

x−abx−4abx−2b

2

x=3(2a−b)

⇒4a+2b−10abx=6a−3b

⇒2a−5b+10abx=0

⇒x=

10ab

5b−2a

y=

2a−b

2−a(

10ab

5b−2a

)−2b(

10ab

5b−2a

)

⇒y=

10ab

2(10ab)−a(5b−2a)−2b(5b−2a)

×

2a−b

1

⇒y=

10ab×(2a−b)

20ab−5ab+2a

2

−10b

2

+4ab

⇒y=

10ab×(2a−b)

19ab+2a

2

−10b

2

⇒y=

10ab

a+10b

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