Math, asked by jyotiberwa2, 7 months ago

Solve:
a. a/5+ 3=2. b. 5t+28=10​

Answers

Answered by ronakkothari45
1

Answer:

a. a/5+3= 2

a+3(5)/5=2

a+15=2× 5

a+15=10

a=10-15

a= -5

b. 5t+28=10

5t= 10- 28

5t= -18

t= -18/5

Answered by Anonymous
0

ANSWER✔

\large\underline\bold{GIVEN,}

\sf\dashrightarrow 1). \dfrac{a}{5} +3=2

\sf\dashrightarrow 2). 5t+28=10

\large\underline\bold{SOLUTION,}

\sf\therefore 1). \dfrac{a}{5} +3=2

\sf\implies \dfrac{a+15}{5} =2

\sf\implies a+15=2 \times 5

\sf\implies a=10-15

\sf\implies a= -5

\large{\boxed{\bf{ \star\:\:a=-5 \:\: \star}}}

\sf\therefore  2). 5t+28=10

\sf\implies 5t=10-28

\sf\implies 5t= -18

\sf\implies t= \dfrac{-18}{5}

\large{\boxed{\bf{ \star\:\:t= \dfrac{-18}{5} \:\: \star}}}

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