Question

solve a^a-b x a^b-a x b^a-b x b^b-a

Answer 1

Step-by-step explanation:

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Answer 2

ANSWER:

To Solve:

$\:\:\:\bullet\:\:\: a^{a-b}\times a^{b-a} \times b^{a-b}\times b^{b-a}$

Solution:

We need to solve,

$\implies a^{a-b}\times a^{b-a} \times b^{a-b}\times b^{b-a}$

$\implies a^{a-b}\times a^{-(a-b)} \times b^{a-b}\times b^{-(a-b)}$

We know that,

$\hookrightarrow x^{-y} = \dfrac{1}{x^y}$

So,

$\implies a^{a-b}\times a^{-(a-b)} \times b^{a-b}\times b^{-(a-b)}$

$\implies a^{a-b}\times \dfrac{1}{a^{a-b}} \times b^{a-b}\times \dfrac{1}{b^{a-b}}$

$\implies \dfrac{ a^{a-b} }{a^{a-b}} \times \dfrac{ b^{a-b} }{b^{a-b}}$

On cancelling the terms,

$\implies 1 \times 1$

Hence,

$\implies 1$

Therefore,

$\implies\bf a^{a-b}\times a^{b-a} \times b^{a-b}\times b^{b-a} = 1$

Formula Used:

• x^-y = 1/x^y