Question

Solve (a+b)² first (a²+b²+2ab)² Then Assume b²+2ab=X (a²+X)²= a⁴+ x²+2a²x So put value of X =a⁴+ (b²+2ab)² +2a²(b²+2ab) = a⁴+b⁴+4a²b²+2ab³+2a²b²+4a³b So now ( (a+b)²)²= a⁴+b⁴+6a²b²+2ab³+4a³b​

Answer 1

Answer:

I don't know this question answer

Step-by-step explanation:

Sorry you can do itself