solve (a-b)^3-(a+b)^3
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a³-3a²b-3ab²+b³-( a³+3a²b+3ab²+b³)
=-6(a²b+ab²)
=-6(a²b+ab²)
renumehra50:
thanks
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As we know the formula;
a^3-a^b+ab^+b^3-(a^3+a^b-ab+b^3)
Now we solve;
a cube -3a square b -3ab square +b cube -(a cube +3a square b - 3ab square + b cube )
= 6(a cube b + ab square)
I hope its definetly help for ur que..☺️
a^3-a^b+ab^+b^3-(a^3+a^b-ab+b^3)
Now we solve;
a cube -3a square b -3ab square +b cube -(a cube +3a square b - 3ab square + b cube )
= 6(a cube b + ab square)
I hope its definetly help for ur que..☺️
if iys wright please mark as brainlist
its
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