Math, asked by FarhanKhan281003, 1 year ago

solve (a-b) (a+b) +(b-c) (b+c) +(c-a) (c+a)

Answers

Answered by Debdipta
1
this is the answer .
Attachments:
Answered by Vishwas111
0
(a-b)^2=(a+b)(a-b)
so a^2-b^2+b^2-c^2+c^2-a^2
then we will cancel +b^2 and -b^2
then we will cancel +c^2 and-c^2
then we will cancel +a^2 and -a^2
And thus the answer is 0
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