solve (a+b+c)2-(a+b-c)2
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1
Answer :
Now,
(a + b + c)² - (a + b - c)²
= (a + b + c + a + b - c)
(a + b + c - a - b + c),
using the identity x² - y² = (x + y) (x - y)
= (2a + 2b) (2c)
= 2 (a + b) × 2c
= 4 (a + b)c
#MarkAsBrainliest
Now,
(a + b + c)² - (a + b - c)²
= (a + b + c + a + b - c)
(a + b + c - a - b + c),
using the identity x² - y² = (x + y) (x - y)
= (2a + 2b) (2c)
= 2 (a + b) × 2c
= 4 (a + b)c
#MarkAsBrainliest
Answered by
1
============
We know, x²-y² = (x + y)(x - y)
============
(a+b+c-a-b+c)(a+b+c+a+b-c)
(2c)(2a + 2b)
(2×2)(c)(a + b)
4ac + 4bc
I hope this will help you
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