Question

solve
(a+b+c)² + (a-b-c)²​

Answer 1

Step-by-step explanation:

As we know that the formula for (a+b+c)^2,

(a+b+c)^2=a^2 + b^2 + c^2 + 2ab + 2bc + 2ac

As, (a-b-c)^2=[a+(-b)+(-c)]^2

Substitute (-b) instead of b and (-c) instead of c in (a+b+c)^2

Therefore,

a^2 +(-b)^2 +(-c)^2 +2a(-b) +2(-b)(-c) +2a(-c)

=> a^2 +b^2 +c^2 -2ab+2bc-2ac

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Answer 2

Answer:

$2( a^2 + b^2 + c^2 +2 bc)$

Step-by-step explanation:

$(a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + ac + bc)$ (1)

$(a - b -c)^2 = a^2 + b^2 + c^2 + 2(- ab - ac + bc)$ (2)

(1) + (2) =>

=  $a^2 + b^2 + c^2 + 2(ab + ac + bc)$ + $a^2 + b^2 + c^2 + 2(- ab - ac + bc)$

= $2( a^2 + b^2 + c^2 + 2bc)$

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