Math, asked by arjunsaneesh3171, 1 year ago

Solve a differential equation x.x.x.dt+cosect.dx=0

Answers

Answered by adityaraj91
0

 {x}^{3} dt   + cosect \: dx \\ 1 \div cosectdt =  {x}^{ - 3} dx \\ itnregation \: onboth \:side \\  \\  ln(sintdt  )  =  ln {x}^{ - 3}  dx \:  + c \\  - cost \:  = 1 \div 2 {x}^{2}  + c
this is your answer. check it.
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