Question

Solve :

a] Equal heat is given to two objects A and B of mass 1 g. Temperature of A increases by 3°C and B by 5 °C.
Which object has more specific heat?
And by what factor? ​

Answer 1

Question:

Equal heat is given to two objects A and B of mass 1 g. Temperature of A increases by 3°C and B by 5 °C. Which object has more specific heat?

And by what factor?

Given:

Mass of object A and B = 1g

Temperature of A = 3°C

Temperature of B = 5°C

Heat given = Q (let)

Let their specific heat be S1 and S2.

We have a formula, $Q=S \Delta m \Delta T$

Where Q is Heat Energy, m is heat, S is specific heat and T is temperature.

Solution:

For object A,

We have:

$Q= S \Delta m \Delta T \\\\ \implies S_1 \times 1 \times 3 \\\\ \implies 3S_1$

For object B,

We have:

$Q= S \Delta m \Delta T \\\\ \implies S_2 \times 1 \times 5 \\\\ \implies 5S_2$

Since, Q is same for both, we have,

$3S_1= 5S_2 \\\\ S_1= \frac{5} {3} S_2$

Hence, Specific heat of A is greater than that of B.

Answer 2

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