Math, asked by ummmmmmmmmmmmmmmmm, 4 months ago

Solve:A) Find the mean of all prime numbers up to 10.
(B) Find the mean proportional between 3 and 27.
(C) Divide 81 in to three parts in the ratio 2 : 3 : 4
(D) Given below figure shows a pair of parallel lines cut by a transversal. Find the
value of a and b, giving reason.

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Answers

Answered by Mahekfarheen
1

Answer:

1.) The all prime numbers upto 30 are 2,3,5,7,11,13,17,19,23,29

sum of these observations=129

Number of their observation=10

Required mean=129÷10=12.9

2.)The mean proportional of 27 and 3 is √27×3=√81=9.

3.)Given ratio=2:3:4

Sum of their ratio=9

1st part=2/9×81=18

2nd part=3/9×81=27

3rd part= 4/9×81=36

4.)Each figure given below shows a pair of parallel lines cut by a transversal For each case, find a and b, giving reasons.

Answered by avantika9c
1

Answer:

A) prime numbers till 30 are as follows

2,3,5,7,11,13,17,19,23 and 29

Hence, the mean can be calculated as below

Mean = Sum of numbers / Number of numbers

(2+3+5+7+11+13+17+19+23+29)/10

We get,

=129/10

=12.9

Therefore, mean=12.9 Answer

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