Question

Solve :

A force of 60N acts on a body of 10cm² cross - section. Calculate the pressure exerted by the body. ​

Answer 1

Given :

• Force (F) = 60 N
• Area of cross-section (A) = 10 cm²

To find :

• Pressure (P)

Solution :

We have,

⟹ F = 60 N

⟹ A = 10/100000 m²

⟹ A = 0.001 m²

We know,

⟹ P = F/A

Hence,

⟹ P = 60/0.001

⟹ P = 60000 Pa

∴ The pressure exerted by the body is 60000 Pa.

Answer 2

Answer:

$60000 \: pascals$

Explanation:

Firstly you've gotta convert area to SI units

${10}^{4} {cm}^{2} = 1 {m}^{2} \\ 10 {cm }^{2} = {10}^{ - 3} {m}^{2}$

Now,

$pressure = force \div area \\ = \frac{60}{ {10}^{ - 3} } \\ = 60 \times {10}^{3} \\ = 60000 \: pascals$

Also, the above answer is wrong because 1m^2 is not equal to 100cm^2.

Hope this helps ;)