Question

Solve:
(a). p²+9p-36​

Answer 1

Step-by-step explanation:

Given:-

P²+9P-36

=>P²+12P-3P-36

=>P(P+12)-3(P+12)

=>(P+12)(P-3)

To get zeroes, equate the given polynomial to 0

=>(P+12)(P-3)=0

=>P+12=0 or P-3=0

=>P=-12 or P=3

The zeroes are 3 and -12

Answer 2

Step-by-step explanation:

p² + 9p - 36

p² + ( 12 - 3 )p - 36

p² + 12p - 3p - 36

p ( p + 12 ) - 3 ( p + 12 )

( p + 12 ) ( p - 3 )

( p + 12 ) = 0 , ( p - 3 ) = 0

p + 12 = 0 , p - 3 = 0

p = - 12 , p = 3