Question

solve (a) part of the following picture

Answer 1

x² -2(a² + b²) + (a²-b²)² = 0 (x - y)² = (x + y)² - 4xy => x²-2(a² + b²) + (a² + b²)² - 4a²b² = 0 (x -y)² = x² - 2xy + y² => (x - (a² + b²))² - (2ab)² = 0 x² - y² = (x+y)(x - y) => (x - (a² + b²) + 2ab) ((x - (a² + b²) - 2ab) = => (x - (a² + b² - 2ab)) (x - (a² + b²+2ab)) = 0 => (x - (a - b)²)(x - (a + b)²) = 0 => x= (a - b)², (a + b)² Hope this helps

Answer 2

Answer:

The roots of the equation_ x^2-2(a^2-b^)x +(a^2-b^)^2=0 are:

x = (a+b)^2 ,(a-b)^2.

Hope it helps you ◕‿◕