solve a quadratic equation
A(x2+1)=(a2+1)x
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ax²+a=a²x+x
ax²-a²x-x+a=0
ax(x-a)-(x-a)
(ax-1)(x-a)
x=1/a , a
ax²-a²x-x+a=0
ax(x-a)-(x-a)
(ax-1)(x-a)
x=1/a , a
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9
Answer:
refer to the attachment
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