Question

solve a quadratic equations by factorization : 3(p²-6)=p(p+5)​

Answer 1

Answer:

3p2 - 18 = p2 + 5p

2p2 -5p - 18 = 0

2p2 + 4p -9p - 18 = 0

2p ( p + 2 ) - 9 ( p + 2 )

(p+2)(2p-9)

Answer 2

factorization:

Step-by-step explanation:

$\ Given \ value: \\\\3(p^2-6)=p(p+5)\\\\\ Solution: \\\\3(p^2-6)=p(p+5)\\\\\rightarrow 3p^2-18=p^2+5p\\\\\rightarrow 3p^2-p^2-18-5p=0\\\\\rightarrow 2p^2-5p-18=0\\\\\rightarrow 2p^2-(9p-4p)-18=0\\\\\rightarrow 2p^2-9p+4p-18=0\\\\\rightarrow p(2p-9)+2(2p-9)=0\\\\\rightarrow (2p-9)(p+2)=0\\\\\rightarrow 2p-9= 0 \ \ \ \ \ \ \ \ \ OR \ \ \ \ \ \ p+2=0\\\\\rightarrow p=\frac{9}{2} \ \ \ \ \ \ \ \ \ OR \ \ \ \ \ \ p=-2$

Learn more:

• Factors: https://brainly.in/question/12411751