Question

Solve:
a) x+9/4=13/2
b) 0.9a=7.2

Answer 1

Given :

Two equations $x+\frac{9}{4} =\frac{13}{2}$ and $0.9a=7.2$

To find :

The value of $x$ and $a$.

Step-by-step explanation:

• The value of $x$ and $a$ can be found by following these steps
• Firstly, take the equation number 1.
• Always bring the numerical to the right hand side of the equation and keep the variables on the left side of the equation to avoid confusion.
• In this case,

       $x+\frac{9}{4} =\frac{13}{2}$

• Take the numerical to the other side of the equation

• Then, the equation will be

        $x=\frac{13}{2} -\frac{9}{4}$

• Take LCM for the RHS of the equation

• Then the equation will become

        $x=\frac{13(2)-9}{4}$

• Remove the brackets

        $x=\frac{26-9}{4}$

• Subtract the numbers

        $x=\frac{17}{4}$

• Do the same for the next equation
• In this case,

        $0.9a=7.2$

• Take the number to the other side of the equation
• Then the equation will become

         $a=\frac{7.2}{0.9}$

• Divide the values

         $a=8$

Final answer :

The value of $x$ is $\frac{17}{4}$ and $a$ is $8$

Answer 2

Answer:

Step-by-step explanation:

a) x + 9/4 = 13/2

x = 13/2 - 9/4 ( ∵ transposing )

x = ( 2 × 13 - 9 ) / 4 = ( 26 - 9 ) / 4 = 17/4 ( ∵ lcm of 2 and 4 is 4 )

∴ x = 17/4 is the answer.

b) 0.9a = 7.2

a = 7.2 / 0.9 (∵ transposing )

= 8 is the answer.