solve (a²-b²) (c²-d²) +4abcd
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( a² - b²)( c² - d²) - 4abcd
= {a²c² -a²d² -b²c² + b²d² } -4abcd
= { a²c² + b²d² - 2abcd} -{ a²d² + b²c² +2abcd}
= { (ac)² + (bd)² -2(ac)(bd)} - {(ad)² + (bc)² +2( ad)( bc) }
= ( ac - bd)² - (ad +bc)²
= ( ac - bd + ad + bc)( ac -bd -ad - bc)
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