Solve (ab+1)² - (ab)² where , b-a = 1
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Originally Answered: Is (a - b) ^2 the same as (b - a) ^2?
Yes its the same.
algebrically (a-b)^2= a2+b2+2ab
(b-a)^2 = a2+b2+2ab.
But is that enough?? It doesnt end there. It has to be seen geometrically.How do we solve for |a-b| = x ??
We know |a-b| is always positive, and one way to go about it is to solve is squaring both the sides to get rid of modulus and we get (a-b)^2.
We started of by calculating for |a-b| and whats |a-b| geometrically??
Its the distance between the points and and b.
So its going to be same ie.., distance from a to b is same as distance from b to a and this is one reason why (a-b)^2= (b-a)^2
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