Question

Solve above question​

Answer 1

Factorise:-

• 3x² - 2x - 8 = 0

Solution:-

• 3x² - 6x + 4x - 8 = 0
• 3x(x-2) +4(x - 2) = 0
• (x-2)(3x+4)=0

x = 2 (or) x = -4/3

negative value is not accepted.

Hence, x = 2.

Answer 2

$\huge \fbox \pink{Answer:}$

$\sf \colorbox{pink} {\red★ \: Ans. 4}$

From an external point, 2 tangents can be drawn to a circle. ::k=2.

$\sf \colorbox{pink} {\red★ \: Ans. 5}$

Look at the pic

$\sf \colorbox{pink} {\red★ \: Ans. 6 }$

Here

$a \ \frac{}{2} - a \ \frac{}{1} = ( - 1) - ( - 1) = - 1 + 1 = 0$

$a \ \frac{}{3} - a \: \frac{}{2} = ( - 1) - ( - 1) = - 1 + 1 = 0$

$a \ \frac{}{4} - a \ \frac{}{3} = ( - 1) - ( - 1) = - 1 + 1 = 0 \: etc.$

i.e. any term- preceding term = 0 a Fixed Number.

Hence the Given list of Numbers Forms an A.P.

$\sf \colorbox{pink} {\red★ \: Ans. 7}$

$3 {x}^{2} - 2x + 8 = 0$

$Comparing \: it \: with \: {ax}^{2} + bx + c = 0$

we Get

$a = 3 ,b = - 2 \: and \: c = 8$

$⇒D = {b}^{2} - 4ac$

$= [( - 2 {)}^{2} - 4(3)(8)]$

$(4 - 96)$

$= - 92$

$\\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$