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Answered by
29
S O L U T I O N
The relation between length and area is
R = ρl/A _[i]
Where ρ being specific resistance is the proportionality constant and depends on the nature of material.
[i] Length = L/2, area = 2A
Putting in Eq [i] we have
R = ρ( L/2 )/2A = ρL/4A
[ii] Length = L, area = A
Putting in Eq [i] we have
R = ρL/A
[iii] Length = 2L area = A/2
Putting in Eq [i] we have
R = ρ 2L/ A/2 = 4ρL/A
As it is understood from above, resistance is minimum only in option b!
Answered by
4
Answer:
So, Resistance is minimum in Wire of Cross-sectional area 2A.
Explanation:
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