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SOLUTION;-
we know,
⇒|a + ib| = √(a² + b²) use this concept here,
⇒so, |1 - i| = √{1² + (-1)²}
= √(1 + 1) = √2
x = 0 but we need non-zero solutions
here, we see , there is no non-zero solution.
so, number of solutions is zero.
we know,
⇒|a + ib| = √(a² + b²) use this concept here,
⇒so, |1 - i| = √{1² + (-1)²}
= √(1 + 1) = √2
x = 0 but we need non-zero solutions
here, we see , there is no non-zero solution.
so, number of solutions is zero.
lava88:
mujhe bhi
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