solve acube-asquare+2=0
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Step-by-step explanation:
a³-a²+2=0
=>a³+a²-2a²-2a+2a+2=0
=>a²(a+1)-2a(a+1)+2(a+1)=0
=>(a+1)(a²-2a+2)=0
since the discriminant of the second term a²-2a+2 is negative, it doesnt has real roots.
so let's equate only a+1 as 0
=>a+1=0
=>a=-1
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