Question

solve after reducing to quadratic equation.. x4-26x2+25=0

Answer 1

${x}^{4} - 26 {x}^{2} + 25 = 0 \\ let \: {x}^{2} = t \\ equation \: becomes \\ {t}^{2} - 26t + 25 = 0 \\ {t}^{2} - 25t - t + 25 = 0 \\ t(t - 25) - 1(t - 25) = 0 \\ (t - 1)(t - 25) = 0 \\ when \: t = 1 \\ x {}^{2} = 1 \\ x = 1 \: and \: - 1 \\ when \: t = 25 \\ {x}^{2} = 25 \\ x = 5 \: and \: - 5 \\ therefore \: x = 1.. - 1..5... - 5$
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