Math, asked by zubinsheikh667, 2 months ago

solve algebraic expressions (a-b)(a-b) - (a+b)(a-b) =​

Answers

Answered by fati03073743
0

Answer:

here you go

Step-by-step explanation:

(a-b)(a-b)-(a+b)(a-b)

→ Here we have (a-b)(a-b) = (a-b)²

& (a+b)(a-b) = a²-b²

→(a-b)² - (a² - b²)

→ a² + b² - 2ab - a² + b²

→ 2b² -2ab

Hence (a-b)(a-b)-(a+b)(a-b) = -2ab

Answered by Rupeshsir
1

Here is a list of Algebraic formulas –

a2 – b2 = (a – b)(a + b)

(a + b)2 = a2 + 2ab + b2

a2 + b2 = (a + b)2 – 2ab

(a – b)2 = a2 – 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca

(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)

a3 – b3 = (a – b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 – ab + b2)

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4

a4 – b4 = (a – b)(a + b)(a2 + b2)

a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)

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