solve algebraic expressions (a-b)(a-b) - (a+b)(a-b) =
Answers
Answer:
here you go
Step-by-step explanation:
(a-b)(a-b)-(a+b)(a-b)
→ Here we have (a-b)(a-b) = (a-b)²
& (a+b)(a-b) = a²-b²
→(a-b)² - (a² - b²)
→ a² + b² - 2ab - a² + b²
→ 2b² -2ab
Hence (a-b)(a-b)-(a+b)(a-b) = -2ab
Here is a list of Algebraic formulas –
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)