Question

solve algebraically the pair of equations 2x-y= 5, 3 X + 2 Y= 11​

Answer 1

Step-by-step explanation:

2x-y =5 -> equation 1

3x+2y=11 -> equation 2

so multiply equation 1 by 2 and then add it to equation 2.

so we get , 4x+ 3x= 10+11

7x= 21

X=3

now put X=3 in equation 1 :- y = (2*3)- 5

y= 1

Answer 2

Answer:

x = 3 , y = 1

Solution:

The given pair of equations is :

2x - y = 5 --------(1)

3x + 2y = 11 ---------(2)

Eq-(1) can be rewritten as ;

=> 2x - y = 5

=> y = 2x - 5 --------(3)

Now,

Putting y = 2x - 5 in eq-(2) , we get ;

=> 3x + 2y = 11

=> 3x + 2(2x - 5) = 11

=> 3x + 4x - 10 = 11

=> 3x + 4x = 11 + 10

=> 7x = 21

=> x = 21/7

=> x = 3

Now,

Putting x = 3 in eq-(3) , we get ;

=> y = 2x - 5

=> y = 2•3 - 5

=> y = 6 - 5

=> y = 1

Hence,

The required answer is :

x = 3 , y = 1