Question

Solve Algebraically x+3y=6 , 2x-3y=12​

Answer 1

Answer:

X = 6 and Y = 0

Step-by-step explanation:

As equation is,

$x + 3y = 6$

which means we have to consider the values so if we consider x=0 then the second equation is not possible which is,

$2x - 3y = 12$

so we will take x=6 and y=0 and put it into both the equations,

$1 ) \: \: (6) + 3(0) = 6$

$= 6 + 0 = 6$

now 1st equation is proved.

Answer 2

Answer:

X = 6

Y = 0

Step-by-step explanation:

x+3y = 6 _______(a)

multiply by 2

2x + 6y = 12 ___(1)

2x-3y = 12 ____(2)

_____________

6y+3y = 12-12

9y = 0

.°. Y = 0

put y = 0 in equation (a)

.°. X + 3(0) = 6

.°. X = 6