Solve all of the above plz
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Sorry for the bad handwriting or if you are not able to understand the step.
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(i) (x+1) (x-1)
=x²- 1
(ii) (3x+2y) (x+6y)
=3x²+ 20xy + 12y²
(iii) (2x-3y) (3x-2y)
=6x²- 13xy - 6y²
Step-by-step explanation:
(i) x(x-1) + 1(x-1)
=x²-x+x-1
=x²-1
(ii) 3x(x + 6y) + 2y(x + 6y)
= 3x² + 18xy + 2xy + 12y²
= 3x² + 20xy + 12y²
(iii) 2x(3x - 2y) - 3y(3x - 2y)
= 6x² - 4xy - 9xy - 6y²
= 6x² - 13xy - 6y²
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